Metamath Proof Explorer


Theorem ax12f

Description: Basis step for constructing a substitution instance of ax-c15 without using ax-c15 . We can start with any formula ph in which x is not free. (Contributed by NM, 21-Jan-2007) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis ax12f.1 φxφ
Assertion ax12f ¬xx=yx=yφxx=yφ

Proof

Step Hyp Ref Expression
1 ax12f.1 φxφ
2 ax-1 φx=yφ
3 1 2 alrimih φxx=yφ
4 3 2a1i ¬xx=yx=yφxx=yφ