Metamath Proof Explorer


Theorem axsegconlem4

Description: Lemma for axsegcon . Show that the distance between two points is a real number. (Contributed by Scott Fenton, 17-Sep-2013)

Ref Expression
Hypothesis axsegconlem2.1 ⊢ S = ∑ p = 1 N A ⁡ p − B ⁡ p 2
Assertion axsegconlem4 ⊢ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N → S ∈ ℝ

Proof

Step Hyp Ref Expression
1 axsegconlem2.1 ⊢ S = ∑ p = 1 N A ⁡ p − B ⁡ p 2
2 1 axsegconlem2 ⊢ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N → S ∈ ℝ
3 1 axsegconlem3 ⊢ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N → 0 ≤ S
4 2 3 resqrtcld ⊢ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N → S ∈ ℝ