Metamath Proof Explorer


Theorem bj-spst

Description: Closed form of sps . Once in main part, prove sps and spsd from it. (Contributed by BJ, 20-Oct-2019)

Ref Expression
Assertion bj-spst ⊢ φ → ψ → ∀ x φ → ψ

Proof

Step Hyp Ref Expression
1 sp ⊢ ∀ x φ → φ
2 1 imim1i ⊢ φ → ψ → ∀ x φ → ψ