Metamath Proof Explorer


Theorem divcan4zi

Description: A cancellation law for division. (Contributed by NM, 12-Oct-1999)

Ref Expression
Hypotheses divclz.1 ⊢ A ∈ ℂ
divclz.2 ⊢ B ∈ ℂ
Assertion divcan4zi ⊢ B ≠ 0 → A ⁢ B B = A

Proof

Step Hyp Ref Expression
1 divclz.1 ⊢ A ∈ ℂ
2 divclz.2 ⊢ B ∈ ℂ
3 divcan4 ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ B ≠ 0 → A ⁢ B B = A
4 1 2 3 mp3an12 ⊢ B ≠ 0 → A ⁢ B B = A