Metamath Proof Explorer


Theorem divmul3d

Description: Relationship between division and multiplication. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses div1d.1 ⊢ φ → A ∈ ℂ
divcld.2 ⊢ φ → B ∈ ℂ
divmuld.3 ⊢ φ → C ∈ ℂ
divassd.4 ⊢ φ → C ≠ 0
Assertion divmul3d ⊢ φ → A C = B ↔ A = B ⁢ C

Proof

Step Hyp Ref Expression
1 div1d.1 ⊢ φ → A ∈ ℂ
2 divcld.2 ⊢ φ → B ∈ ℂ
3 divmuld.3 ⊢ φ → C ∈ ℂ
4 divassd.4 ⊢ φ → C ≠ 0
5 divmul3 ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ C ≠ 0 → A C = B ↔ A = B ⁢ C
6 1 2 3 4 5 syl112anc ⊢ φ → A C = B ↔ A = B ⁢ C