Metamath Proof Explorer


Theorem divmulsd

Description: Relationship between surreal division and multiplication. (Contributed by Scott Fenton, 16-Mar-2025)

Ref Expression
Hypotheses divmulsd.1 ⊢ φ → A ∈ No
divmulsd.2 ⊢ φ → B ∈ No
divmulsd.3 ⊢ φ → C ∈ No
divmulsd.4 ⊢ φ → C ≠ 0 s
Assertion divmulsd ⊢ φ → A / su C = B ↔ C ⋅ s B = A

Proof

Step Hyp Ref Expression
1 divmulsd.1 ⊢ φ → A ∈ No
2 divmulsd.2 ⊢ φ → B ∈ No
3 divmulsd.3 ⊢ φ → C ∈ No
4 divmulsd.4 ⊢ φ → C ≠ 0 s
5 3 4 recsexd ⊢ φ → ∃ x ∈ No C ⋅ s x = 1 s
6 1 2 3 4 5 divmulswd ⊢ φ → A / su C = B ↔ C ⋅ s B = A