Metamath Proof Explorer


Theorem efadd

Description: Sum of exponents law for exponential function. (Contributed by NM, 10-Jan-2006) (Proof shortened by Mario Carneiro, 29-Apr-2014)

Ref Expression
Assertion efadd ⊢ A ∈ ℂ ∧ B ∈ ℂ → e A + B = e A ⁢ e B

Proof

Step Hyp Ref Expression
1 eqid ⊢ n ∈ ℕ 0 ⟼ A n n ! = n ∈ ℕ 0 ⟼ A n n !
2 eqid ⊢ n ∈ ℕ 0 ⟼ B n n ! = n ∈ ℕ 0 ⟼ B n n !
3 eqid ⊢ n ∈ ℕ 0 ⟼ A + B n n ! = n ∈ ℕ 0 ⟼ A + B n n !
4 simpl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ∈ ℂ
5 simpr ⊢ A ∈ ℂ ∧ B ∈ ℂ → B ∈ ℂ
6 1 2 3 4 5 efaddlem ⊢ A ∈ ℂ ∧ B ∈ ℂ → e A + B = e A ⁢ e B