Metamath Proof Explorer


Theorem funALTVeqd

Description: Equality deduction for the function predicate. (Contributed by NM, 23-Feb-2013)

Ref Expression
Hypothesis funALTVeqd.1 ⊢ φ → A = B
Assertion funALTVeqd ⊢ φ → FunALTV A ↔ FunALTV B

Proof

Step Hyp Ref Expression
1 funALTVeqd.1 ⊢ φ → A = B
2 funALTVeq ⊢ A = B → FunALTV A ↔ FunALTV B
3 1 2 syl ⊢ φ → FunALTV A ↔ FunALTV B