Metamath Proof Explorer


Theorem funALTVeqd

Description: Equality deduction for the function predicate. (Contributed by NM, 23-Feb-2013)

Ref Expression
Hypothesis funALTVeqd.1 φA=B
Assertion funALTVeqd φFunALTVAFunALTVB

Proof

Step Hyp Ref Expression
1 funALTVeqd.1 φA=B
2 funALTVeq A=BFunALTVAFunALTVB
3 1 2 syl φFunALTVAFunALTVB