Metamath Proof Explorer


Theorem in31

Description: A rearrangement of intersection. (Contributed by NM, 27-Aug-2012)

Ref Expression
Assertion in31 ABC=CBA

Proof

Step Hyp Ref Expression
1 in12 CAB=ACB
2 incom ABC=CAB
3 incom CBA=ACB
4 1 2 3 3eqtr4i ABC=CBA