Metamath Proof Explorer


Theorem neeq1i

Description: Inference for inequality. (Contributed by NM, 29-Apr-2005) (Proof shortened by Wolf Lammen, 19-Nov-2019)

Ref Expression
Hypothesis neeq1i.1 A=B
Assertion neeq1i ACBC

Proof

Step Hyp Ref Expression
1 neeq1i.1 A=B
2 1 eqeq1i A=CB=C
3 2 necon3bii ACBC