Metamath Proof Explorer


Theorem nfcvf

Description: If x and y are distinct, then x is not free in y . Usage of this theorem is discouraged because it depends on ax-13 . See nfcv for a version that replaces the distinctor with a disjoint variable condition, requiring fewer axioms. (Contributed by Mario Carneiro, 8-Oct-2016) Avoid ax-ext . (Revised by Wolf Lammen, 10-May-2023) (New usage is discouraged.)

Ref Expression
Assertion nfcvf ¬xx=y_xy

Proof

Step Hyp Ref Expression
1 nfv w¬xx=y
2 nfv xwz
3 elequ2 z=ywzwy
4 2 3 dvelimnf ¬xx=yxwy
5 1 4 nfcd ¬xx=y_xy