Metamath Proof Explorer


Theorem pm2.61ine

Description: Inference eliminating an inequality in an antecedent. (Contributed by NM, 16-Jan-2007) (Proof shortened by Andrew Salmon, 25-May-2011)

Ref Expression
Hypotheses pm2.61ine.1 A = B φ
pm2.61ine.2 A B φ
Assertion pm2.61ine φ

Proof

Step Hyp Ref Expression
1 pm2.61ine.1 A = B φ
2 pm2.61ine.2 A B φ
3 nne ¬ A B A = B
4 3 1 sylbi ¬ A B φ
5 2 4 pm2.61i φ