Metamath Proof Explorer


Theorem recjd

Description: Real part of a complex conjugate. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypothesis recld.1 ⊢ φ → A ∈ ℂ
Assertion recjd ⊢ φ → ℜ ⁡ A ‾ = ℜ ⁡ A

Proof

Step Hyp Ref Expression
1 recld.1 ⊢ φ → A ∈ ℂ
2 recj ⊢ A ∈ ℂ → ℜ ⁡ A ‾ = ℜ ⁡ A
3 1 2 syl ⊢ φ → ℜ ⁡ A ‾ = ℜ ⁡ A