Metamath Proof Explorer


Theorem spcgft

Description: A closed version of spcgf . (Contributed by Andrew Salmon, 6-Jun-2011) (Revised by Mario Carneiro, 4-Jan-2017)

Ref Expression
Hypotheses spcimgfi1.1 ⊢ Ⅎ x ψ
spcimgfi1.2 ⊢ Ⅎ _ x A
Assertion spcgft ⊢ ∀ x x = A → φ ↔ ψ → A ∈ B → ∀ x φ → ψ

Proof

Step Hyp Ref Expression
1 spcimgfi1.1 ⊢ Ⅎ x ψ
2 spcimgfi1.2 ⊢ Ⅎ _ x A
3 biimp ⊢ φ ↔ ψ → φ → ψ
4 3 imim2i ⊢ x = A → φ ↔ ψ → x = A → φ → ψ
5 4 alimi ⊢ ∀ x x = A → φ ↔ ψ → ∀ x x = A → φ → ψ
6 1 2 spcimgfi1 ⊢ ∀ x x = A → φ → ψ → A ∈ B → ∀ x φ → ψ
7 5 6 syl ⊢ ∀ x x = A → φ ↔ ψ → A ∈ B → ∀ x φ → ψ