Metamath Proof Explorer


Theorem spcimgfi1

Description: A closed version of spcimgf . (Contributed by Mario Carneiro, 4-Jan-2017) (Proof shortened by Wolf Lammen, 27-Jul-2025)

Ref Expression
Hypotheses spcimgfi1.1 ⊢ Ⅎ x ψ
spcimgfi1.2 ⊢ Ⅎ _ x A
Assertion spcimgfi1 ⊢ ∀ x x = A → φ → ψ → A ∈ B → ∀ x φ → ψ

Proof

Step Hyp Ref Expression
1 spcimgfi1.1 ⊢ Ⅎ x ψ
2 spcimgfi1.2 ⊢ Ⅎ _ x A
3 spcimgft ⊢ Ⅎ _ x A ∧ Ⅎ x ψ ∧ ∀ x x = A → φ → ψ → A ∈ B → ∀ x φ → ψ
4 2 1 3 mpanl12 ⊢ ∀ x x = A → φ → ψ → A ∈ B → ∀ x φ → ψ