Metamath Proof Explorer


Theorem ssdifsym

Description: Symmetric class differences for subclasses. (Contributed by AV, 3-Jan-2022)

Ref Expression
Assertion ssdifsym ⊢ A ⊆ V ∧ B ⊆ V → B = V ∖ A ↔ A = V ∖ B

Proof

Step Hyp Ref Expression
1 ssdifim ⊢ A ⊆ V ∧ B = V ∖ A → A = V ∖ B
2 1 ex ⊢ A ⊆ V → B = V ∖ A → A = V ∖ B
3 ssdifim ⊢ B ⊆ V ∧ A = V ∖ B → B = V ∖ A
4 3 ex ⊢ B ⊆ V → A = V ∖ B → B = V ∖ A
5 2 4 anbiim ⊢ A ⊆ V ∧ B ⊆ V → B = V ∖ A ↔ A = V ∖ B