Metamath Proof Explorer


Theorem subrngss

Description: A subring is a subset. (Contributed by AV, 14-Feb-2025)

Ref Expression
Hypothesis subrngss.1 B=BaseR
Assertion subrngss Could not format assertion : No typesetting found for |- ( A e. ( SubRng ` R ) -> A C_ B ) with typecode |-

Proof

Step Hyp Ref Expression
1 subrngss.1 B=BaseR
2 1 issubrng Could not format ( A e. ( SubRng ` R ) <-> ( R e. Rng /\ ( R |`s A ) e. Rng /\ A C_ B ) ) : No typesetting found for |- ( A e. ( SubRng ` R ) <-> ( R e. Rng /\ ( R |`s A ) e. Rng /\ A C_ B ) ) with typecode |-
3 2 simp3bi Could not format ( A e. ( SubRng ` R ) -> A C_ B ) : No typesetting found for |- ( A e. ( SubRng ` R ) -> A C_ B ) with typecode |-