Metamath Proof Explorer


Theorem 0exp0e1

Description: 0 ^ 0 = 1 . This is our convention. It follows the convention used by Gleason; see Part of Definition 10-4.1 of Gleason p. 134. (Contributed by David A. Wheeler, 8-Dec-2018)

Ref Expression
Assertion 0exp0e1 ( 0 ↑ 0 ) = 1

Proof

Step Hyp Ref Expression
1 0cn 0 ∈ ℂ
2 exp0 ( 0 ∈ ℂ → ( 0 ↑ 0 ) = 1 )
3 1 2 ax-mp ( 0 ↑ 0 ) = 1