Metamath Proof Explorer


Theorem a1dd

Description: Double deduction introducing an antecedent. Deduction associated with a1d . Double deduction associated with ax-1 and a1i . (Contributed by NM, 17-Dec-2004) (Proof shortened by Mel L. O'Cat, 15-Jan-2008)

Ref Expression
Hypothesis a1dd.1 ( 𝜑 → ( 𝜓𝜒 ) )
Assertion a1dd ( 𝜑 → ( 𝜓 → ( 𝜃𝜒 ) ) )

Proof

Step Hyp Ref Expression
1 a1dd.1 ( 𝜑 → ( 𝜓𝜒 ) )
2 ax-1 ( 𝜒 → ( 𝜃𝜒 ) )
3 1 2 syl6 ( 𝜑 → ( 𝜓 → ( 𝜃𝜒 ) ) )