Metamath Proof Explorer


Theorem elsuc

Description: Membership in a successor. Exercise 5 of TakeutiZaring p. 17. (Contributed by NM, 15-Sep-2003)

Ref Expression
Hypothesis elsuc.1 𝐴 ∈ V
Assertion elsuc ( 𝐴 ∈ suc 𝐵 ↔ ( 𝐴𝐵𝐴 = 𝐵 ) )

Proof

Step Hyp Ref Expression
1 elsuc.1 𝐴 ∈ V
2 elsucg ( 𝐴 ∈ V → ( 𝐴 ∈ suc 𝐵 ↔ ( 𝐴𝐵𝐴 = 𝐵 ) ) )
3 1 2 ax-mp ( 𝐴 ∈ suc 𝐵 ↔ ( 𝐴𝐵𝐴 = 𝐵 ) )