Metamath Proof Explorer


Theorem elsuc2

Description: Membership in a successor. (Contributed by NM, 15-Sep-2003)

Ref Expression
Hypothesis elsuc.1 𝐴 ∈ V
Assertion elsuc2 ( 𝐵 ∈ suc 𝐴 ↔ ( 𝐵𝐴𝐵 = 𝐴 ) )

Proof

Step Hyp Ref Expression
1 elsuc.1 𝐴 ∈ V
2 elsuc2g ( 𝐴 ∈ V → ( 𝐵 ∈ suc 𝐴 ↔ ( 𝐵𝐴𝐵 = 𝐴 ) ) )
3 1 2 ax-mp ( 𝐵 ∈ suc 𝐴 ↔ ( 𝐵𝐴𝐵 = 𝐴 ) )