Metamath Proof Explorer


Theorem eqeq2i

Description: Inference from equality to equivalence of equalities. (Contributed by NM, 26-May-1993)

Ref Expression
Hypothesis eqeq2i.1 𝐴 = 𝐵
Assertion eqeq2i ( 𝐶 = 𝐴𝐶 = 𝐵 )

Proof

Step Hyp Ref Expression
1 eqeq2i.1 𝐴 = 𝐵
2 eqeq2 ( 𝐴 = 𝐵 → ( 𝐶 = 𝐴𝐶 = 𝐵 ) )
3 1 2 ax-mp ( 𝐶 = 𝐴𝐶 = 𝐵 )