Metamath Proof Explorer


Theorem fveq2

Description: Equality theorem for function value. (Contributed by NM, 29-Dec-1996)

Ref Expression
Assertion fveq2 ( 𝐴 = 𝐵 → ( 𝐹𝐴 ) = ( 𝐹𝐵 ) )

Proof

Step Hyp Ref Expression
1 breq1 ( 𝐴 = 𝐵 → ( 𝐴 𝐹 𝑥𝐵 𝐹 𝑥 ) )
2 1 iotabidv ( 𝐴 = 𝐵 → ( ℩ 𝑥 𝐴 𝐹 𝑥 ) = ( ℩ 𝑥 𝐵 𝐹 𝑥 ) )
3 df-fv ( 𝐹𝐴 ) = ( ℩ 𝑥 𝐴 𝐹 𝑥 )
4 df-fv ( 𝐹𝐵 ) = ( ℩ 𝑥 𝐵 𝐹 𝑥 )
5 2 3 4 3eqtr4g ( 𝐴 = 𝐵 → ( 𝐹𝐴 ) = ( 𝐹𝐵 ) )