Theorem gcdn0val

Description: The value of the gcd operator when at least one operand is nonzero. (Contributed by Paul Chapman, 21-Mar-2011)

	Ref	Expression
Assertion	gcdn0val	⊢ ( ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ ¬ ( 𝑀 = 0 ∧ 𝑁 = 0 ) ) → ( 𝑀 gcd 𝑁 ) = sup ( { 𝑛 ∈ ℤ ∣ ( 𝑛 ∥ 𝑀 ∧ 𝑛 ∥ 𝑁 ) } , ℝ , < ) )

Proof

Step	Hyp	Ref	Expression
1		gcdval	⊢ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( 𝑀 gcd 𝑁 ) = if ( ( 𝑀 = 0 ∧ 𝑁 = 0 ) , 0 , sup ( { 𝑛 ∈ ℤ ∣ ( 𝑛 ∥ 𝑀 ∧ 𝑛 ∥ 𝑁 ) } , ℝ , < ) ) )
2		iffalse	⊢ ( ¬ ( 𝑀 = 0 ∧ 𝑁 = 0 ) → if ( ( 𝑀 = 0 ∧ 𝑁 = 0 ) , 0 , sup ( { 𝑛 ∈ ℤ ∣ ( 𝑛 ∥ 𝑀 ∧ 𝑛 ∥ 𝑁 ) } , ℝ , < ) ) = sup ( { 𝑛 ∈ ℤ ∣ ( 𝑛 ∥ 𝑀 ∧ 𝑛 ∥ 𝑁 ) } , ℝ , < ) )
3	1 2	sylan9eq	⊢ ( ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ ¬ ( 𝑀 = 0 ∧ 𝑁 = 0 ) ) → ( 𝑀 gcd 𝑁 ) = sup ( { 𝑛 ∈ ℤ ∣ ( 𝑛 ∥ 𝑀 ∧ 𝑛 ∥ 𝑁 ) } , ℝ , < ) )