Metamath Proof Explorer


Theorem nbfal

Description: The negation of a proposition is equivalent to itself being equivalent to F. . (Contributed by Anthony Hart, 14-Aug-2011)

Ref Expression
Assertion nbfal ( ¬ 𝜑 ↔ ( 𝜑 ↔ ⊥ ) )

Proof

Step Hyp Ref Expression
1 fal ¬ ⊥
2 1 nbn ( ¬ 𝜑 ↔ ( 𝜑 ↔ ⊥ ) )