Metamath Proof Explorer


Theorem nfci

Description: Deduce that a class A does not have x free in it. (Contributed by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypothesis nfci.1 𝑥 𝑦𝐴
Assertion nfci 𝑥 𝐴

Proof

Step Hyp Ref Expression
1 nfci.1 𝑥 𝑦𝐴
2 df-nfc ( 𝑥 𝐴 ↔ ∀ 𝑦𝑥 𝑦𝐴 )
3 2 1 mpgbir 𝑥 𝐴