Metamath Proof Explorer


Theorem nfcvf

Description: If x and y are distinct, then x is not free in y . Usage of this theorem is discouraged because it depends on ax-13 . See nfcv for a version that replaces the distinctor with a disjoint variable condition, requiring fewer axioms. (Contributed by Mario Carneiro, 8-Oct-2016) Avoid ax-ext . (Revised by Wolf Lammen, 10-May-2023) (New usage is discouraged.)

Ref Expression
Assertion nfcvf ( ¬ ∀ 𝑥 𝑥 = 𝑦 𝑥 𝑦 )

Proof

Step Hyp Ref Expression
1 nfv 𝑤 ¬ ∀ 𝑥 𝑥 = 𝑦
2 nfv 𝑥 𝑤𝑧
3 elequ2 ( 𝑧 = 𝑦 → ( 𝑤𝑧𝑤𝑦 ) )
4 2 3 dvelimnf ( ¬ ∀ 𝑥 𝑥 = 𝑦 → Ⅎ 𝑥 𝑤𝑦 )
5 1 4 nfcd ( ¬ ∀ 𝑥 𝑥 = 𝑦 𝑥 𝑦 )