Metamath Proof Explorer


Theorem nfeqf1

Description: An equation between setvar is free of any other setvar. Usage of this theorem is discouraged because it depends on ax-13 . (Contributed by Wolf Lammen, 10-Jun-2019) (New usage is discouraged.)

Ref Expression
Assertion nfeqf1 ( ¬ ∀ 𝑥 𝑥 = 𝑦 → Ⅎ 𝑥 𝑦 = 𝑧 )

Proof

Step Hyp Ref Expression
1 nfeqf2 ( ¬ ∀ 𝑥 𝑥 = 𝑦 → Ⅎ 𝑥 𝑧 = 𝑦 )
2 equcom ( 𝑧 = 𝑦𝑦 = 𝑧 )
3 2 nfbii ( Ⅎ 𝑥 𝑧 = 𝑦 ↔ Ⅎ 𝑥 𝑦 = 𝑧 )
4 1 3 sylib ( ¬ ∀ 𝑥 𝑥 = 𝑦 → Ⅎ 𝑥 𝑦 = 𝑧 )