Metamath Proof Explorer


Theorem nfim

Description: If x is not free in ph and ps , then it is not free in ( ph -> ps ) . Inference associated with nfimt . (Contributed by Mario Carneiro, 11-Aug-2016) (Proof shortened by Wolf Lammen, 2-Jan-2018) df-nf changed. (Revised by Wolf Lammen, 17-Sep-2021)

Ref Expression
Hypotheses nfim.1 𝑥 𝜑
nfim.2 𝑥 𝜓
Assertion nfim 𝑥 ( 𝜑𝜓 )

Proof

Step Hyp Ref Expression
1 nfim.1 𝑥 𝜑
2 nfim.2 𝑥 𝜓
3 nfimt ( ( Ⅎ 𝑥 𝜑 ∧ Ⅎ 𝑥 𝜓 ) → Ⅎ 𝑥 ( 𝜑𝜓 ) )
4 1 2 3 mp2an 𝑥 ( 𝜑𝜓 )