Metamath Proof Explorer


Theorem nfor

Description: If x is not free in ph and ps , then it is not free in ( ph \/ ps ) . (Contributed by NM, 5-Aug-1993) (Revised by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypotheses nf.1 𝑥 𝜑
nf.2 𝑥 𝜓
Assertion nfor 𝑥 ( 𝜑𝜓 )

Proof

Step Hyp Ref Expression
1 nf.1 𝑥 𝜑
2 nf.2 𝑥 𝜓
3 df-or ( ( 𝜑𝜓 ) ↔ ( ¬ 𝜑𝜓 ) )
4 1 nfn 𝑥 ¬ 𝜑
5 4 2 nfim 𝑥 ( ¬ 𝜑𝜓 )
6 3 5 nfxfr 𝑥 ( 𝜑𝜓 )