Metamath Proof Explorer


Theorem opeq1i

Description: Equality inference for ordered pairs. (Contributed by NM, 16-Dec-2006)

Ref Expression
Hypothesis opeq1i.1 𝐴 = 𝐵
Assertion opeq1i 𝐴 , 𝐶 ⟩ = ⟨ 𝐵 , 𝐶

Proof

Step Hyp Ref Expression
1 opeq1i.1 𝐴 = 𝐵
2 opeq1 ( 𝐴 = 𝐵 → ⟨ 𝐴 , 𝐶 ⟩ = ⟨ 𝐵 , 𝐶 ⟩ )
3 1 2 ax-mp 𝐴 , 𝐶 ⟩ = ⟨ 𝐵 , 𝐶