Metamath Proof Explorer


Theorem oveq

Description: Equality theorem for operation value. (Contributed by NM, 28-Feb-1995)

Ref Expression
Assertion oveq ( 𝐹 = 𝐺 → ( 𝐴 𝐹 𝐵 ) = ( 𝐴 𝐺 𝐵 ) )

Proof

Step Hyp Ref Expression
1 fveq1 ( 𝐹 = 𝐺 → ( 𝐹 ‘ ⟨ 𝐴 , 𝐵 ⟩ ) = ( 𝐺 ‘ ⟨ 𝐴 , 𝐵 ⟩ ) )
2 df-ov ( 𝐴 𝐹 𝐵 ) = ( 𝐹 ‘ ⟨ 𝐴 , 𝐵 ⟩ )
3 df-ov ( 𝐴 𝐺 𝐵 ) = ( 𝐺 ‘ ⟨ 𝐴 , 𝐵 ⟩ )
4 1 2 3 3eqtr4g ( 𝐹 = 𝐺 → ( 𝐴 𝐹 𝐵 ) = ( 𝐴 𝐺 𝐵 ) )