Metamath Proof Explorer


Theorem recsval

Description: Strong transfinite recursion in terms of all previous values. (Contributed by Stefan O'Rear, 18-Jan-2015)

Ref Expression
Assertion recsval ( 𝐴 ∈ On → ( recs ( 𝐹 ) ‘ 𝐴 ) = ( 𝐹 ‘ ( recs ( 𝐹 ) ↾ 𝐴 ) ) )

Proof

Step Hyp Ref Expression
1 eqid recs ( 𝐹 ) = recs ( 𝐹 )
2 1 tfr2 ( 𝐴 ∈ On → ( recs ( 𝐹 ) ‘ 𝐴 ) = ( 𝐹 ‘ ( recs ( 𝐹 ) ↾ 𝐴 ) ) )