Metamath Proof Explorer


Theorem sbcg

Description: Substitution for a variable not occurring in a wff does not affect it. Distinct variable form of sbcgf . (Contributed by Alan Sare, 10-Nov-2012)

Ref Expression
Assertion sbcg ( 𝐴𝑉 → ( [ 𝐴 / 𝑥 ] 𝜑𝜑 ) )

Proof

Step Hyp Ref Expression
1 nfv 𝑥 𝜑
2 1 sbcgf ( 𝐴𝑉 → ( [ 𝐴 / 𝑥 ] 𝜑𝜑 ) )