Metamath Proof Explorer


Theorem ss2in

Description: Intersection of subclasses. (Contributed by NM, 5-May-2000)

Ref Expression
Assertion ss2in ( ( 𝐴𝐵𝐶𝐷 ) → ( 𝐴𝐶 ) ⊆ ( 𝐵𝐷 ) )

Proof

Step Hyp Ref Expression
1 ssrin ( 𝐴𝐵 → ( 𝐴𝐶 ) ⊆ ( 𝐵𝐶 ) )
2 sslin ( 𝐶𝐷 → ( 𝐵𝐶 ) ⊆ ( 𝐵𝐷 ) )
3 1 2 sylan9ss ( ( 𝐴𝐵𝐶𝐷 ) → ( 𝐴𝐶 ) ⊆ ( 𝐵𝐷 ) )