Metamath Proof Explorer


Theorem sumeq2d

Description: Equality deduction for sum. Note that unlike sumeq2dv , k may occur in ph . (Contributed by NM, 1-Nov-2005)

Ref Expression
Hypothesis sumeq2d.1 ( 𝜑 → ∀ 𝑘𝐴 𝐵 = 𝐶 )
Assertion sumeq2d ( 𝜑 → Σ 𝑘𝐴 𝐵 = Σ 𝑘𝐴 𝐶 )

Proof

Step Hyp Ref Expression
1 sumeq2d.1 ( 𝜑 → ∀ 𝑘𝐴 𝐵 = 𝐶 )
2 sumeq2 ( ∀ 𝑘𝐴 𝐵 = 𝐶 → Σ 𝑘𝐴 𝐵 = Σ 𝑘𝐴 𝐶 )
3 1 2 syl ( 𝜑 → Σ 𝑘𝐴 𝐵 = Σ 𝑘𝐴 𝐶 )