Metamath Proof Explorer


Theorem syl5reqr

Description: An equality transitivity deduction. (Contributed by NM, 29-Mar-1998)

Ref Expression
Hypotheses syl5reqr.1 𝐵 = 𝐴
syl5reqr.2 ( 𝜑𝐵 = 𝐶 )
Assertion syl5reqr ( 𝜑𝐶 = 𝐴 )

Proof

Step Hyp Ref Expression
1 syl5reqr.1 𝐵 = 𝐴
2 syl5reqr.2 ( 𝜑𝐵 = 𝐶 )
3 1 eqcomi 𝐴 = 𝐵
4 3 2 syl5req ( 𝜑𝐶 = 𝐴 )