Metamath Proof Explorer


Theorem syl6eqelr

Description: A membership and equality inference. (Contributed by NM, 4-Jan-2006)

Ref Expression
Hypotheses syl6eqelr.1 ( 𝜑𝐵 = 𝐴 )
syl6eqelr.2 𝐵𝐶
Assertion syl6eqelr ( 𝜑𝐴𝐶 )

Proof

Step Hyp Ref Expression
1 syl6eqelr.1 ( 𝜑𝐵 = 𝐴 )
2 syl6eqelr.2 𝐵𝐶
3 1 eqcomd ( 𝜑𝐴 = 𝐵 )
4 3 2 syl6eqel ( 𝜑𝐴𝐶 )