Metamath Proof Explorer


Theorem syl6eqr

Description: An equality transitivity deduction. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypotheses syl6eqr.1 ( 𝜑𝐴 = 𝐵 )
syl6eqr.2 𝐶 = 𝐵
Assertion syl6eqr ( 𝜑𝐴 = 𝐶 )

Proof

Step Hyp Ref Expression
1 syl6eqr.1 ( 𝜑𝐴 = 𝐵 )
2 syl6eqr.2 𝐶 = 𝐵
3 2 eqcomi 𝐵 = 𝐶
4 1 3 syl6eq ( 𝜑𝐴 = 𝐶 )