Metamath Proof Explorer


Table of Contents - 10.7.3.38. Condition for a non-unital ring to be unital

In MathOverflow, the following theorem is claimed: "Theorem 1. Let A be a rng (= nonunital associative ring). Let J be a (two-sided) ideal of A. Assume that both rngs J and A/J are unital. Then, the rng A is also unital.", see https://mathoverflow.net/questions/487676 (/unitality-of-rngs-is-inherited-by-extensions).

This thread also contains some hints to literature: Clifford and Preston's book "The Algebraic Theory of Semigroups"(Chapter 5 on representation theory), and Okninski's book Semigroup Algebras, Corollary 8 in Chapter 4.

In the following, this theorem is proven formally, see rngringbdlem2 (and variants rngringbd and ring2idlqusb).

This theorem is not trivial, since it is possible for a subset of a ring, especially a subring of a non-unital ring or (left/two-sided) ideal, to be a unital ring with a different ring unity. See also the comment for df-subrg. In the given case, however, the ring unity of the larger ring can be determined by the ring unity of the two-sided ideal and a representative of the ring unity of the corresponding quotient, see ring2idlqus1. An example for such a construction is given in pzriprng1ALT, for the case mentioned in the comment for df-subrg.

  1. rngqiprng1elbas
  2. rngqiprngghmlem1
  3. rngqiprngghmlem2
  4. rngqiprngghmlem3
  5. rngqiprngimfolem
  6. rngqiprnglinlem1
  7. rngqiprnglinlem2
  8. rngqiprnglinlem3
  9. rngqiprngimf1lem
  10. rngqipbas
  11. rngqiprng
  12. rngqiprngimf
  13. rngqiprngimfv
  14. rngqiprngghm
  15. rngqiprngimf1
  16. rngqiprngimfo
  17. rngqiprnglin
  18. rngqiprngho
  19. rngqiprngim
  20. rng2idl1cntr
  21. rngringbdlem1
  22. rngringbdlem2
  23. rngringbd
  24. ring2idlqus
  25. ring2idlqusb
  26. rngqiprngfulem1
  27. rngqiprngfulem2
  28. rngqiprngfulem3
  29. rngqiprngfulem4
  30. rngqiprngfulem5
  31. rngqipring1
  32. rngqiprngfu
  33. rngqiprngu
  34. ring2idlqus1