Metamath Proof Explorer


Theorem 13an22anass

Description: Associative law for four conjunctions with a triple conjunction. (Contributed by Thierry Arnoux, 21-Jan-2025) (Proof shortened by Wolf Lammen, 31-Oct-2026)

Ref Expression
Assertion 13an22anass
|- ( ( ph /\ ( ps /\ ch /\ th ) ) <-> ( ( ph /\ ps ) /\ ( ch /\ th ) ) )

Proof

Step Hyp Ref Expression
1 3anass
 |-  ( ( ps /\ ch /\ th ) <-> ( ps /\ ( ch /\ th ) ) )
2 1 bianass
 |-  ( ( ph /\ ( ps /\ ch /\ th ) ) <-> ( ( ph /\ ps ) /\ ( ch /\ th ) ) )