Theorem 1p0e1

Description: 1 + 0 = 1. (Contributed by David A. Wheeler, 8-Dec-2018)

	Ref	Expression
Assertion	1p0e1	|- ( 1 + 0 ) = 1

Proof

Step	Hyp	Ref	Expression
1		ax-1cn	|- 1 e. CC
2	1	addid1i	|- ( 1 + 0 ) = 1