Theorem 3coml

Description: Commutation in antecedent. Rotate left. (Contributed by NM, 28-Jan-1996)

	Ref	Expression
Hypothesis	3exp.1	|- ( ( ph /\ ps /\ ch ) -> th )
Assertion	3coml	|- ( ( ps /\ ch /\ ph ) -> th )

Proof

Step	Hyp	Ref	Expression
1		3exp.1	|- ( ( ph /\ ps /\ ch ) -> th )
2	1	3com23	|- ( ( ph /\ ch /\ ps ) -> th )
3	2	3com13	|- ( ( ps /\ ch /\ ph ) -> th )