Metamath Proof Explorer
Description: A deduction from three chained equalities. (Contributed by NM, 4-Aug-1995) (Proof shortened by Andrew Salmon, 25-May-2011)
|
|
Ref |
Expression |
|
Hypotheses |
3eqtr4d.1 |
|- ( ph -> A = B ) |
|
|
3eqtr4d.2 |
|- ( ph -> C = A ) |
|
|
3eqtr4d.3 |
|- ( ph -> D = B ) |
|
Assertion |
3eqtr4d |
|- ( ph -> C = D ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
3eqtr4d.1 |
|- ( ph -> A = B ) |
2 |
|
3eqtr4d.2 |
|- ( ph -> C = A ) |
3 |
|
3eqtr4d.3 |
|- ( ph -> D = B ) |
4 |
3 1
|
eqtr4d |
|- ( ph -> D = A ) |
5 |
2 4
|
eqtr4d |
|- ( ph -> C = D ) |