Metamath Proof Explorer


Theorem 3eqtrrd

Description: A deduction from three chained equalities. (Contributed by NM, 4-Aug-2006) (Proof shortened by Andrew Salmon, 25-May-2011)

Ref Expression
Hypotheses 3eqtrd.1
|- ( ph -> A = B )
3eqtrd.2
|- ( ph -> B = C )
3eqtrd.3
|- ( ph -> C = D )
Assertion 3eqtrrd
|- ( ph -> D = A )

Proof

Step Hyp Ref Expression
1 3eqtrd.1
 |-  ( ph -> A = B )
2 3eqtrd.2
 |-  ( ph -> B = C )
3 3eqtrd.3
 |-  ( ph -> C = D )
4 1 2 eqtrd
 |-  ( ph -> A = C )
5 4 3 eqtr2d
 |-  ( ph -> D = A )