Metamath Proof Explorer
Description: A deduction from three chained equalities. (Contributed by NM, 4-Aug-2006) (Proof shortened by Andrew Salmon, 25-May-2011)
|
|
Ref |
Expression |
|
Hypotheses |
3eqtrd.1 |
|- ( ph -> A = B ) |
|
|
3eqtrd.2 |
|- ( ph -> B = C ) |
|
|
3eqtrd.3 |
|- ( ph -> C = D ) |
|
Assertion |
3eqtrrd |
|- ( ph -> D = A ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
3eqtrd.1 |
|- ( ph -> A = B ) |
2 |
|
3eqtrd.2 |
|- ( ph -> B = C ) |
3 |
|
3eqtrd.3 |
|- ( ph -> C = D ) |
4 |
1 2
|
eqtrd |
|- ( ph -> A = C ) |
5 |
4 3
|
eqtr2d |
|- ( ph -> D = A ) |