Theorem 3expia

Description: Exportation from triple conjunction. (Contributed by NM, 19-May-2007) (Proof shortened by Wolf Lammen, 22-Jun-2022)

	Ref	Expression
Hypothesis	3exp.1	|- ( ( ph /\ ps /\ ch ) -> th )
Assertion	3expia	|- ( ( ph /\ ps ) -> ( ch -> th ) )

Proof

Step	Hyp	Ref	Expression
1		3exp.1	|- ( ( ph /\ ps /\ ch ) -> th )
2	1	3expb	|- ( ( ph /\ ( ps /\ ch ) ) -> th )
3	2	expr	|- ( ( ph /\ ps ) -> ( ch -> th ) )