Metamath Proof Explorer


Theorem 3netr3g

Description: Substitution of equality into both sides of an inequality. (Contributed by NM, 24-Jul-2012)

Ref Expression
Hypotheses 3netr3g.1
|- ( ph -> A =/= B )
3netr3g.2
|- A = C
3netr3g.3
|- B = D
Assertion 3netr3g
|- ( ph -> C =/= D )

Proof

Step Hyp Ref Expression
1 3netr3g.1
 |-  ( ph -> A =/= B )
2 3netr3g.2
 |-  A = C
3 3netr3g.3
 |-  B = D
4 2 3 neeq12i
 |-  ( A =/= B <-> C =/= D )
5 1 4 sylib
 |-  ( ph -> C =/= D )