Metamath Proof Explorer


Theorem 3sstr3i

Description: Substitution of equality in both sides of a subclass relationship. (Contributed by NM, 13-Jan-1996) (Proof shortened by Eric Schmidt, 26-Jan-2007)

Ref Expression
Hypotheses 3sstr3.1
|- A C_ B
3sstr3.2
|- A = C
3sstr3.3
|- B = D
Assertion 3sstr3i
|- C C_ D

Proof

Step Hyp Ref Expression
1 3sstr3.1
 |-  A C_ B
2 3sstr3.2
 |-  A = C
3 3sstr3.3
 |-  B = D
4 2 3 sseq12i
 |-  ( A C_ B <-> C C_ D )
5 1 4 mpbi
 |-  C C_ D