Theorem 4p1e5

Description: 4 + 1 = 5. (Contributed by Mario Carneiro, 18-Apr-2015)

	Ref	Expression
Assertion	4p1e5	|- ( 4 + 1 ) = 5

Proof

Step	Hyp	Ref	Expression
1		df-5	|- 5 = ( 4 + 1 )
2	1	eqcomi	|- ( 4 + 1 ) = 5