Metamath Proof Explorer


Theorem 5lt6

Description: 5 is less than 6. (Contributed by Mario Carneiro, 15-Sep-2013)

Ref Expression
Assertion 5lt6
|- 5 < 6

Proof

Step Hyp Ref Expression
1 5re
 |-  5 e. RR
2 1 ltp1i
 |-  5 < ( 5 + 1 )
3 df-6
 |-  6 = ( 5 + 1 )
4 2 3 breqtrri
 |-  5 < 6